Weigh abd against egh. If the 3 balls from C didn't match the 3 balls from A in your second weighing, you now know if the unusual ball is too light or too heavy. if they balance, then the other ball is the lighter or heavier one, if not that is the one ! Take 6 balls and split them into 2 groups of 3 balls each. 2 weighings to find the slightly heavier ball. There are 12 balls, all of equal size. Go to Step 2a. Split the n balls into 3 groups of O/3, or as close as possible (at least two of the groups will have the same # of balls). You are also given a two-pan balance to use. You donât know that the defective one is heavier or lighter than other balls. You have 12 identical balls. You have a set of balance scales which will give 3 possible readings: Left = Right, Left > Right, or; Left < Right (ie Left and Right have equal weight, Left is Heavier, or Left is Lighter). However, one of the balls is heavier or lighter. From these three balls, discard one of them and choose the other two to weigh. If the scale balances, the third ball is the oddball. The other ball is either heavier or lighter. What's the fewest number of times you'd have to use the balance to find out which ball is different, and if it is heavier or lighter than the others. You have an even number of balls, $2n$ identical balls, and half of them are Heavy balls (weight $=x$) and the rest half are Light balls (weight $=y$). If they balance, 9 is fake (heavier). Using one weighing we have successfully narrowed three groups down to one. Arash. If the genuine balls are heavier, then the counterfeit is a light ball, and vice-versa. So, in two weighings, the maximum reduction of possibilities is a factor of 9 If you have 8 balls, and do not know whether the odd one out is heavier or lighter, you have sixteen possibilities. If a < g or a > g, g is the odd one. A terrorist has implanted one of the balls with explosives, but they add such a small amount that no one can tell the difference. 0 0. RickB. 0 0. A second comparison will determine whether the oddball is lighter or heavier than the other two balls. Now you know the heavy ball is one of two possibilities. Then take the heavier group of four and divide them again, two on one side of the scale, and two on the other. Separating Heavier from the Lighter Balls. Split the balls into 4 groups of 3. Many bowling pro shops will let you try bowling balls of different weights to determine which one is best for you. If one is heavier than the other, then you know that group contains the bomb. If it's not completely clear how we can make the assumption that the bad coins is in group 7,8 & 9 when the scales balance, remember we know there is a bad coin, there has to be, we have eliminated the other two groups, it â¦ By the way, although you now know which ball is odd, you may still not know if it's heavier or lighter. Is it possible with only 3?if yes how do we do it?thanks! There are twelve identical-looking balls, but one is either heavier or lighter than the other eleven. 12 golf ball riddle 12 golf balls all appear same-one weighs slightly different-heavier or lighter scales and 3 uses. You have 12 balls identical in size and appearance but 1 is an odd weight (could be either light or heavy). Lv 7. One more trial will identify which balls â¦ You have 12 balls all look identical (in shape, color etc.). Unless you know whether it's heavier or lighter, two weighings looks impossible.The maximum you can reduce possibilities by is a factor of three per weighing. If a group is known to be heavier or lighter, it can be determined by weighing one ball against another. You cannot reduce 16 to 1 in two weighings. Weigh {8, 9} and {10, 11} (Note: 8 is surely not fake) balance - If they balance, we know 12 is the fake one. If the balls weigh the same then the third ball is the heavy one and we again have our answer. 8 balls, you don't know if the odd one is heavier/lighter. 1 decade ago. The solution is simple for any # O. If one of the two balls is lighter than the other one being weighed, it is the lighter ball. $2$. If they are not equal, the ball that matches the group as heavier or lighter, is the heavier or lighter ball. How will you find which ball is different? Otherwise, the third ball is the bomb. Now we know that one of the two balls is lighter or heavier than the rest. Use the scale to weigh the 2 groups. 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